In an ap sum of first n terms is 3n 2/2
WebLet S n denotes the sum of first n terms of the AP. ∴ s n = 3n 2 + 5n. ⇒ `s_(n-1) = 3 (n-1) ^2 + 5 (n-1)` = `3(n^2 - 2n + 1) + 5 (n-1)` =`3n^2 -n-2` Now , n th term of AP , a n = s n - s n-1 = (3n 2 + 5n ) - ( 3n 2-n-2) = 6n + 2 . Let d be the common difference of the AP. ∴ d = a n - a n-1 = (6n + 2 ) - [ 6(n-1 ) +2] = 6n + 2 - 6 (n-1) -2 = 6
In an ap sum of first n terms is 3n 2/2
Did you know?
WebJan 22, 2024 · If sum of n terms of AP is denoted as 2n² + 3n, than find the common Difference d of AP. Points To Remember :--- • A sequence is said to be in AP (Arithmetic Progression), if the difference between its consecutive terms are equal. • The nth term of an AP is given as ; T (n) = a + (n-1)•d , where a is the first term and d is the common difference. WebIn an AP, the sum of first n terms is 3n^22 + 13n2 Find the 25th term. Class 11 >> Applied Mathematics >> Sequences and series >> Arithmetic progression >> In an AP, the sum of …
WebMay 5, 2024 · In an AP the sum of first n terms is n/2 (3n+5) find the 25th term of the AP CBSE Class 10 Maths - YouTube 0:00 / 2:21 In an AP the sum of first n terms is... WebMar 30, 2024 · Given Sn = 2n2 + 3n Taking n = 1 S1 = 2 12 + 3 1 = 2 + 3 = 5 So, Sum of first term of AP is 5 But sum of first term will be the first term So, First term = a = 5 Taking n = …
WebWhat is the value of x in the equation 2^(x+1) - 3(2^x) + 2 = 0? If the sum of the first n terms of an arithmetic sequence is given by S = 3n^2 - 2n, what is the common difference of the sequence? what is the degree of a polynomial 5x⁴+6x²-8x-9 WebMar 3, 2024 · Given that Sum to n terms of an AP is . 3n² + n. Given common difference is 6, If suppose a is the first term of A.P and 'd' is the . common difference, the Sum to n terms of an A.P is. given by Sn = (n/2)*[2a + (n - 1)d] Given Sn = 3n² + n. If we substitute n = 1 , in Sn we get Sum to 1 tems of an A.P . which is equivalent to first term of A ...
WebMar 23, 2024 · The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. 3. A ladder has rungs 25 cm apart. (see Fig. 5.7). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top.
WebIf the sum of the first n terms of an AP is 2n (n+3), then what is the series? first we will simplify the bracket 2n (n+3)=2n^2+6n If n=1 then 2*1^2+6*1=8 so our s1 is 8 If n=2 then 2*2^2+6*2=20 So our s2 is 20 if n=3 then 2*3^2+6*3=36 So our s3 is 36 then a1 is 8 a2 is s2-s1 that is 20–8=12 a3 is s3-s2 that is 36–20=16 so our ap is 8,12,16…. how good is parrying in elden ringWeb4 rows · 2 × Sum = n×(a+l) ⇒ Sum = n/2(a+l) Substituting the value of l in the previous equation, ... how good is phengoldWebAug 28, 2024 · Let the sum of n terms be given by Sn so Sn = 3n²/2+ 5n/2 S1 = 3 (1)²/2 + 5 (1)/2 = 3/2+5/2 => 4 so 1st term is 4 say 'a' Now S2 = 3 (2)²/2 + 5 (2)/2 = 6+5 => 11 Now a2 … highest opening weekend box office 2022WebSep 15, 2024 · Solution: We can use our concept of AP here to solve the problem as follows: Step 1: Calculate the first number divisible by 3 in the given range: 20 = 3 × 6 + 2 a = 20 + (3 - remainder) a = 20 + (3 - 2) a = 21. Step 2: Calculate the Last number (nth) in the given range:-. how good is parker house furnitureWebAn arithmetic progression or arithmetic sequence (AP) is a sequence of numbers such that the difference from any succeeding term to its preceding term remains constant throughout the sequence. The constant difference is called common difference of that arithmetic progression. For instance, the sequence 5, 7, 9, 11, 13, 15, . . . is an arithmetic progression … how good is pet insuranceWebThe sum of first n terms of an A.P is 5n−n 2. Find the n th term of this A.P A 6−5n B 6−2n C 5−2n D None of these Easy Solution Verified by Toppr Correct option is B) Given, S n=5n−n 2 S 1=a 1=5(1)−1 2=4 S 2=5(2)−2 2=6 a 2=S 2−a 1=6−4=2 d=a 2−a 1=2−4=−2 a n=a+(n−1)d a n=4+(n−1)(−2) ∴a n=6−2n Was this answer helpful? 0 0 Similar questions Find highest opening weekend movie of all timeWebIt is given that sum of the first n terms of an A.P. is 3n 2 + 6n. ∴ First term = a = S 1 = 3 (1) 2 + 6 (1) = 9. Sum of first two terms = S 2 = 3 (2) 2 + 6 (2) = 24. ∴ Second term = S 2 − S 1 = 24 − 9 = 15. ∴ Common difference = d = Second term − First term = 15 − 9 = 6 Also, n th term = a n = a + (n − 1)d ⇒ a n = 9 + (n − 1)6 ⇒ a n = 9 + 6n − 6 highest ops in mlb season